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Question: A food packet is dropped from a helicopter rising up with a velocity of \(4m{s^{ - 1}}\) . The veloc...

A food packet is dropped from a helicopter rising up with a velocity of 4ms14m{s^{ - 1}} . The velocity of the packet after three seconds will be:
A) 20.4ms120.4m{s^{ - 1}}
B) 25.4ms125.4m{s^{ - 1}}
C) 28.4ms128.4m{s^{ - 1}}
D) 30.4ms130.4m{s^{ - 1}}

Explanation

Solution

This question utilises the concept of relative motion and free fall under gravity. Since the food packet is “dropped” from the helicopter, it does not have any initial velocity of its own. Its initial velocity is only relative to the helicopter which is rising against the direction of motion of the packet.

Formulae used:
v=u+gtv = u + gt
where gg is the acceleration due to gravity, uu is the initial velocity of the food packet, tt is the time passed and vv is the final velocity of the food packet.

Complete step by step solution:
To find the initial velocity of the food packet, we look at it with respect to the helicopter. Right before the fall, the helicopter was rising up with a velocity of 4ms14m{s^{ - 1}} . This implies that the food packet was also rising up with a velocity of 4ms14m{s^{ - 1}}.

For sake of simplicity, we can assume the downward direction to be positive. Therefore, the available data is;
g=+9.8ms2g = + 9.8m{s^{ - 2}} where gg is the acceleration due to gravity.
u=4ms1u = - 4m{s^{ - 1}} where uu is the initial velocity of the food packet.
t=3st = 3s where tt is the time passed
vv is the final velocity of the food packet. Now the first equation of free-fall motion is;
v=u+gtv = u + gt
where gg is the acceleration due to gravity, uu is the initial velocity of the food packet, tt is the time passed and vv is the final velocity of the food packet.
v=4+9.8×3\Rightarrow v = - 4 + 9.8 \times 3
v=4+9.8×3\Rightarrow v = - 4 + 9.8 \times 3
v=4+29.4\Rightarrow v = - 4 + 29.4
v=25.4ms1\Rightarrow v = 25.4m{s^{ - 1}}

Therefore the velocity of the food packet after 3s3s is (B),25.4ms1(B), 25.4m{s^{ - 1}}.

Note: In such questions, it is important to check the direction of the initial velocity to avoid calculation mistakes. When an object is dropped from anywhere, by default it is not given any initial velocity of its own. In such cases, the initial velocity is due to inertia of motion.