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Chemistry Question on Chemical Kinetics

A following mechanism has been proposed for a reaction 2A + B→\to D + EA + B→\to C + D (slow)A + C →\to E (fast) .The rate law expression for the reaction is

A

r=k[A]2[B]r = k [A]^2 [B]

B

r=k[A][B]r = k [A] [B]

C

r=k[A]2r = k [A]^2

D

r = k [A] [C]

Answer

r=k[A][B]r = k [A] [B]

Explanation

Solution

Rate is controlled by slowest step