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Question: A flywheel rotating at 420 rpm slows down at a constant rate of 2 rad s-2. The time required to stop...

A flywheel rotating at 420 rpm slows down at a constant rate of 2 rad s-2. The time required to stop the flywheel is

A

22 s

B

11s

C

44 s

D

12 s

Answer

22 s

Explanation

Solution

Here, v0=420rpm=7rpsv _ { 0 } = 420 \mathrm { rpm } = 7 \mathrm { rps }

∴t=ω−ω0α=−44−2=22 s\therefore \mathrm { t } = \frac { \omega - \omega _ { 0 } } { \alpha } = \frac { - 44 } { - 2 } = 22 \mathrm {~s}