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Question

Question: In the figure shown, the heavy cylinder (radius R) resting on a smooth surface separates two liquids...

In the figure shown, the heavy cylinder (radius R) resting on a smooth surface separates two liquids of densities 2p and 3p. Find the height 'h' for the equilibrium of cylinder.

Answer

The problem statement is incomplete as the weight of the cylinder or its dimensions are not provided, which are necessary to solve for the equilibrium height 'h'.

Explanation

Solution

To find the height 'h' for the equilibrium of the cylinder, we need to equate the buoyant forces acting on the cylinder to its weight. Let WW be the weight of the cylinder. The cylinder is partially submerged in a liquid of density 2ρ2\rho up to height hh, and it is also in contact with a liquid of density 3ρ3\rho.

The buoyant force due to the liquid of density 2ρ2\rho is FB1=(2ρ)gV1F_{B1} = (2\rho) g V_1, where V1V_1 is the volume of the cylinder submerged in this liquid. The buoyant force due to the liquid of density 3ρ3\rho is FB2=(3ρ)gV2F_{B2} = (3\rho) g V_2, where V2V_2 is the volume of the cylinder submerged in this liquid.

For equilibrium, the sum of the buoyant forces must balance the weight of the cylinder: W=FB1+FB2W = F_{B1} + F_{B2} W=(2ρ)gV1+(3ρ)gV2W = (2\rho) g V_1 + (3\rho) g V_2

From the figure, it is implied that the cylinder is partially submerged in the lower liquid (density 2ρ2\rho) up to a height hh. The upper liquid (density 3ρ3\rho) is above this. The problem statement mentions the cylinder is "resting on a smooth surface" and "separates two liquids". This phrasing is somewhat ambiguous. If the cylinder is resting on a surface at the bottom, then the lower liquid is 2ρ2\rho and the upper liquid is 3ρ3\rho. If the cylinder is floating, then the weight must be balanced by the buoyant forces.

Assuming the cylinder is floating and partially submerged in the liquid of density 2ρ2\rho up to height hh, and the liquid of density 3ρ3\rho is above it. The volume submerged in the lower liquid is V1V_1. The volume submerged in the upper liquid is V2V_2. The total submerged volume is Vsubmerged=V1+V2V_{submerged} = V_1 + V_2.

However, without the weight of the cylinder (WW) or its total height and density, we cannot determine the specific value of hh. The problem statement is incomplete.