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Question: A flood light is covered with a filter that transmits red light. The electric field of emerging beam...

A flood light is covered with a filter that transmits red light. The electric field of emerging beam is represented by a sinusoidal plane wave Ex=36sin(1.20×107z+6×1015t)V/m{E_x} = 36\sin (1.20 \times {10^7}z + 6 \times {10^{15}}t)V/m. The average intensity of beam will be
A. 0.86W/m20.86W/{m^2}
B. 1.72W/m21.72W/{m^2}
C. 3.44W/m23.44W/{m^2}
D. 6.88W/m26.88W/{m^2}

Explanation

Solution

Here to find average intensity we will use the formula Iavg.=c×(E0)2×ε02{I_{avg.}} = \dfrac{{c \times {{\left( {{E_0}} \right)}^2} \times {\varepsilon _0}}}{2},where is speed of light, is amplitude of electric field as given in question and is constant value known as epsilon naught.

Complete step-by-step solution:
Variant electric field, Ex=36sin(1.20×107z+6×1015t)V/m{E_x} = 36\sin (1.20 \times {10^7}z + 6 \times {10^{15}}t)V/m
Amplitude of electric field, E0=36{E_0} = 36
Speed of light, c=3×108c = 3 \times {10^8}
Epsilon naught, ε0=8.85×1012Nm2C2{\varepsilon _0} = 8.85 \times {10^{ - 12}}N{m^2}{C^{ - 2}}
So to calculate average intensity, substitute the values as per given in question in the formula Iavg.=c×(E0)2×ε02{I_{avg.}} = \dfrac{{c \times {{\left( {{E_0}} \right)}^2} \times {\varepsilon _0}}}{2}
Iavg.=3×108×8.85×1012×(36)22\Rightarrow {I_{avg.}} = \dfrac{{3 \times {{10}^8} \times 8.85 \times {{10}^{ - 12}} \times {{\left( {36} \right)}^2}}}{2}
Iavg.=3×8.85×104×12962\Rightarrow {I_{avg.}} = \dfrac{{3 \times 8.85 \times {{10}^{ - 4}} \times 1296}}{2}
Iavg.=26.55×1296×1042\Rightarrow {I_{avg.}} = \dfrac{{26.55 \times 1296 \times {{10}^{ - 4}}}}{2}
Iavg.=34408.8×1042\Rightarrow {I_{avg.}} = \dfrac{{34408.8 \times {{10}^{ - 4}}}}{2}
Iavg.=17204.4×104\Rightarrow {I_{avg.}} = 17204.4 \times {10^{ - 4}}
Iavg.=1.72W/m2\Rightarrow {I_{avg.}} = 1.72W/{m^2}

Additional Information: Electric charge is conveyed by the subatomic particles of a molecule, for example, electrons and photons. Each charged molecule makes a space around it where the impact of its electric power is felt. This space around the charged particles is known as the Electric field. At whatever point a unit test charge is set in this electric field it will encounter the power produced by the source molecule. The measure of power experienced by a unit charged molecule when it is set in the electric field is known as Electric field force.

Note:- Electromagnetic beam is synchronize oscillations of electric and magnetic fields by moving charges on any axis generally perpendicular to z axis and oscillating alternatively and perpendicularly to each other and the energy carried by any wave is proportional to its amplitude squared where E0{E_0} is maximum electric field strength of a sinusoidal wave as given in above question and in above question it is varying with respect to both distance and time.