Question

A flask contains argon and oxygen in the ratio of 3 : 2 in mass and the mixture is kept at 27°C. The ratio of their average kinetic energy per molecule respectively will be

• A. 3 : 2
• B. 9 : 4
• C. 2 : 3
• D. 1 : 1

Answer 1

Answer: (D)

1 : 1

Answer 2

The correct answer is (D): 1 : 1

$KE_{avg}$ = $\frac{3}{2}$ $KT$ ( At Lower temperature )

As temperature is same for both the gases.
⇒ Both gases will have same average kinetic energy.

⇒ $\frac{(KE_{avg})_{argon}}{(KE_{avg})_{oxygen}}$ = $\frac{1}{1}$