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Question: A flash light is covered with a filter that transmits red light. The electric field of the emerging ...

A flash light is covered with a filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave Ex=36sin(1.20×107z3.6×1015t)V/m\mathbf{E}_{\mathbf{x}}\mathbf{= 36}\mathbf{\sin}\mathbf{(}\mathbf{1.20}\mathbf{\times}\mathbf{1}\mathbf{0}^{\mathbf{7}}\mathbf{z}\mathbf{-}\mathbf{3.6}\mathbf{\times}\mathbf{1}\mathbf{0}^{\mathbf{15}}\mathbf{t)V/m}. The average intensity of the beam will be

A

0.866muW/m20.86\mspace{6mu} W/m^{2}

B

1.726muW/m21.72\mspace{6mu} W/m^{2}

C

3.446muW/m23.44\mspace{6mu} W/m^{2}

D

6.886muW/m26.88\mspace{6mu} W/m^{2}

Answer

1.726muW/m21.72\mspace{6mu} W/m^{2}

Explanation

Solution

Iav=cε0E022=3×108×8.85×1015×3622=1.726muW/m2I_{av} = \frac{c\varepsilon_{0}E_{0}^{2}}{2} = \frac{3 \times 10^{8} \times 8.85 \times 10^{- 15} \times 36^{2}}{2} = 1.72\mspace{6mu} W/m^{2}