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Question: A flag-staff of 5m high stands on a building of 25 m high. At an observer at a height of 30m. The fl...

A flag-staff of 5m high stands on a building of 25 m high. At an observer at a height of 30m. The flag-staff and the building subtend equal angles. The distance of the observer from the top of the flag-staff is

A

532\frac { 5 \sqrt { 3 } } { 2 }

B

C

D

None of these

Answer

Explanation

Solution

We have, tanα=5x\tan \alpha = \frac { 5 } { x } and tan2α=30x\tan 2 \alpha = \frac { 30 } { x }

\therefore tan2α=305cotα\tan 2 \alpha = \frac { 30 } { 5 \cot \alpha }tan2α=6tanα\tan 2 \alpha = 6 \tan \alpha

33tan2α=13 - 3 \tan ^ { 2 } \alpha = 1tanα=23\tan \alpha = \sqrt { \frac { 2 } { 3 } }

x=5cotα=532x = 5 \cot \alpha = 5 \sqrt { \frac { 3 } { 2 } }