Question

A five digit number is formed by digits 1,2,3,4,5,6,8 without repetition. The probability that number so formed has odd digits at both ends =

• A. $\frac { 2 } { 7 }$
• B. $\frac { 1 } { 14 }$
• C. $\frac { 1 } { 7 }$
• D. None of these

Answer 1

Answer: (B)

$\frac { 1 } { 14 }$

Answer 2

1,2,3,4,5,6,8

favour =

= 3 × (5 × 4 × 3) × 2 = 360

P = $\frac { 360 } { { } ^ { 7 } \mathrm { P } _ { 5 } }$ = $\frac { 1 } { 14 }$