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Chemistry Question on Chemical Kinetics

A first order reaction has the rate constant, k=46×103s1k =46 \times 10^{-3} s ^{-1} The number of correct statement/s from the following is/are _______
Given: log3=0.48\log 3=0.48
A. Reaction completes in 1000s1000 \,s
B. The reaction has a half-life of 500s500 \, s
C. The time required for 10%10 \% completion is 25 times the time required for 90%90 \% completion
D. The degree of dissociation is equal to (1ekt)\left(1-e^{-k t}\right)
E. The rate and the rate constant have the same unit

Answer

The correct answer is 2.
t10%​=K1​ln(a−xa​)=K1​ln(90100​)
t10%​=K2.303​(log10−log9)
t10%​=K2.093​×(0.04)
Similarly
t90%​=K1​ln(10100​)
t90%​=K2.303​
t10%​t90%​​=0.041​=25
ekt=a−xa​
aa−x​=e−kt
1−ax​=e−kt
x=a(1−e−kt)
α=ax​=(1−e−kt)