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Question: A first order reaction has a rate constant \(1.15 \times 10^{- 3}s^{- 1}\) how long will 5 g of this...

A first order reaction has a rate constant 1.15×103s11.15 \times 10^{- 3}s^{- 1} how long will 5 g of this reactant take to reduce to 3 g?

A

444 s

B

400 s

C

528 s

D

669 s

Answer

444 s

Explanation

Solution

t=2.303klogR0R=2.3031.15×103log53t = \frac{2.303}{k}\log\frac{R_{0}}{R} = \frac{2.303}{1.15 \times 10^{- 3}}\log\frac{5}{3}

=2.00×103log1.667=2×103×0.2219=444s= 2.00 \times 10^{3}\log 1.667 = 2 \times 10^{3} \times 0.2219 = 444s