Question
Question: A first order reaction has a rate constant \(1.15 \times {10^{ - 3}}{s^{ - 1}}\). How long will 5 g ...
A first order reaction has a rate constant 1.15×10−3s−1. How long will 5 g of this reactant take to reduce to 3 g?
(A) 444 s
(B) 400 s
(C) 528 s
(D) 669 s
Solution
The reaction is called first order reaction when Rate of reaction depends upon concentration of one reactant only.
Example:
2H2O2(g)→2H2O(l)+O2
Rate=k[H2O2]
This reaction is first order because Rate of reaction is the first power of H2O2 concentration.
Formula used: t=k2.303log10AtAo
Complete step by step answer:
As the reaction is first order reaction therefore formula used is
t=k2.303log10AtAo______(1)
Where,
t = time
k = Rate constant of first order reaction
Ao = Initial concentration
At = Final concentration
The values are
k=1.15×10−3s−1
Ao=5gm
At=3gm
t=?
Substituting this values in equation number (1) we get
t=1.15×10−32.303log35
t=1.15×10−32.303log1.66
Value of log1.66=0.22
Putting this value we have t=1.15×10−32.303×10.22
t=1.552.303×0.22×103
t=1.55506.66
t=440.57sec.
Therefore, from the above explanation the correct option is (A) 444 s.
Additional information: Overall order of reaction is the sum of the exponent to which concentration terms in the rate law are raised.
Let us consider a reaction.
aA+bB→cA+dD
Here the number of molecules of A reacts with the B molecule.
The order of reaction is not related to the stoichiometric equation of reaction.
It means order of reaction is not equal to = a + b
It is an experimentally determined quantity.
Note: The reaction order is always defined in terms of the concentration of reactant and not of product.
Rate constant for first order depends only on time not concentration reactant.