Question

A fireman wants to slide down a rope. The breaking load for the rope is $\frac{3}{4}$th of the weight of the man. With what acceleration should the fireman slide down? (Acceleration due to gravity is g)

• A. $\frac{g}{2}$
• B. $\frac{g}{4}$
• C. $\frac{3g}{4}$
• D. Zero

Answer 1

Answer: (B)

$\frac{g}{4}$

Answer 2

Let the resultant acceleration of fireman be a then $\, \, \, \, \, \, \, \, \, \,$ R = mg - ma Given $\, \, \, \, \, \, \, \, \, \, \, \, \, R = \frac{3}{4} mg$ $\therefore \, \, \, \, \, \, \, \, \, \frac{3}{4} mg = mg - ma \Rightarrow a = \frac{g}{4}$