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Question: A fire wood board floats in fresh water with \(60\% \) of its volume under water. The density of the...

A fire wood board floats in fresh water with 60%60\% of its volume under water. The density of the wood in is g/cm3g/c{{m}^{3}}
(a) 0.40.4:
(b) 0.50.5
(c) 0.60.6
(d) <0.4 < 0.4

Explanation

Solution

In order to calculate the density of the wood in g/cm3g/c{m^3}. It is known that density is inversely proportional to the volume. To calculate the density of the wood directly, there is a formula i.e.
d1d2=v1v2\dfrac{{{d_1}}}{{{d_2}}} = \dfrac{{{v_1}}}{{{v_2}}} where d1{{d}_{1}} is the density of wood outside the water, d2{d_2} is the density of wood inside the water, v1{{v}_{1}} is the volume of wood outside the water and v2{v_2} is the volume of wood inside the water.

Complete step by step solution
Now, from the question,
d1d2=v1v2\dfrac{{{d}_{1}}}{{{d}_{2}}}=\dfrac{{{v}_{1}}}{{{v}_{2}}}
=d1d2=4060=\dfrac{{{d}_{1}}}{{{d}_{2}}}=\dfrac{40}{60}
d1d2=0.66g/cm3\dfrac{{{d_1}}}{{{d_2}}} = 0.66g/c{m^3}
As it is the same material i.e. firewood, the density of the fire wood is 0.66g/cm30.66g/c{{m}^{3}}.

Additional Information: Density and Volume are inversely proportional to each other. Mass and volume are not the same. Thus, we can say that, For a fixed mass, when density increases, volume decreases.Density expresses the amount of mass an object holds within its volume.Volume is the space confined within a closed three-dimensional space. It can be a space that a substance holds or shape occupies.Density and volume are scientific concepts pertaining to physical properties and characteristics of matter. Volume refers to the measurement of the amount of three-dimensional space occupied by an object. Unlike mass, volume changes according to the external conditions. Density refers to the mass contained in a substance for a given volume. It determines how densely molecules of a given object are packed into a given volume.

Note: This question can also be solved using different method i.e. We know, Buoyant force = mass of water displaced and p= mass/volumep=~\text{mass}/\text{volume}. Therefore, p=v/V×p=v\prime /V\times density of water which was assumed to be 1g/cm31g/c{{m}^{3}}.