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Question

Question: (a) Find out the position of the image of an object situated \[A\] in the plane mirror (in figure 1)...

(a) Find out the position of the image of an object situated AA in the plane mirror (in figure 1).
(b) Can Paheli at BB see this image
(c) Can Boojho at CC see this image
(d) When Paheli moves from B to C,B{\text{ }}to{\text{ }}C,where does the image of AA move

Explanation

Solution

To solve any problem with light we have to first see the diagram and have to understand the image formation, then we can solve this. Here paheli, Boojho are two-person; we have to change their position to look for the proper answer to the given answer.

Complete step by step answer:
bbYes from BB can see this image
cc yes Boojho can see the image form CC
let, u be the distance from object
vv be the distance from image
PP is focal length then,
1v+1u=1f=0\dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f} = 0
f= for plane mirror\because f = \infty {\text{ }}for{\text{ }}plane{\text{ }}mirror
1u=1v\dfrac{1}{u} = - \dfrac{1}{v}
Taking derivative in both sides,
1u2u˙1v2v˙=0 v˙=v2u2u˙ v˙=u˙ - \dfrac{1}{{{u^2}}}\dot u - \dfrac{1}{{{v^2}}}\dot v = 0 \\\ \dot v = \dfrac{{{v^2}}}{{{u^2}}}\dot u \\\ \dot v = - \dot u \\\
[vu=1,v2u2=1]\left[ {\because \dfrac{v}{u} = - 1,\dfrac{{{v^2}}}{{{u^2}}} = 1} \right]
Object is not moving , so the image will be at the same position.
\therefore If Paheli moves from BB to CC the image will be in the same position.

Note: Always when you are going to observe this problem use diagrams to see the position of the persons. Then you can easily understand the movement of them. By diagram of this question, we can say the following problems. Also here we used the derivatives because here a movement is given to change with a particular distance so we use derivatives.