Question

A fighter plane is pulling out for a dive at 900 km/h in a vertical circle of radius 2km. Its mass is 5000 kg. Find the force exerted by the air on it at the lowest point.

• A. 2.0625×10⁴N upward
• B. 2.0625×10⁵N downward
• C. 2.0625×10⁵N upward
• D. 2.0625×10⁴N downward

Answer 1

Answer: (C)

2.0625×10⁵N upward

Answer 2

$\frac{mv^{2}}{r} + mg = \frac{5 \times 10^{3} \times (250)^{2}}{2 \times 10^{3}} + 5 \times 10^{4} = 2.0625 \times 10^{5}Nupwards$