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Question

Physics Question on thermal properties of matter

A faulty thermometer has 90.5∘ C90.5^{\circ} \,C and 0.5∘ C0.5^{\circ} \,C as upper and lower fixed points respectively. What is the correct temperature if this faulty thermometer reads 15.5∘C15.5^{\circ} C

A

16.67∘C16.67^{\circ} C

B

16∘C16^{\circ} C

C

15∘C15^{\circ} C

D

15.5∘C15.5^{\circ} C

Answer

16.67∘C16.67^{\circ} C

Explanation

Solution

If a thermometer is wrong calibrated then, If XX the temperature reading on the faulty thermometer scale then, t=(X−LFP)(UFP−LFP)×100t =\frac{( X - LFP )}{( UFP - LFP )} \times 100 where, t=t = actual reading. So, UFP =90.5∘C,LFP=0.5∘C=90.5^{\circ} C , LFP =0.5^{\circ} C for a faulty reading of X=15.5∘CX =15.5^{\circ} C the actual reading can be found by using above formula is =16.67∘C=16.67^{\circ} C