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Question: A dumbell consisting of two masses m each, connected by a light rigid rod of length , falls on two p...

A dumbell consisting of two masses m each, connected by a light rigid rod of length , falls on two pads of equal height, one steel and the other brass through a height h. The co-efficients of restitution are e1 and e2 (e1< e2). To what maximum height will the centre of mass of the dumbell rise after bouncing off the pads?

A

he1+e2\frac{h}{e_{1} + e_{2}}

B

(e1+e2)2h4\frac{h}{4}

C

e12+e224\frac{e_{1}^{2} + e_{2}^{2}}{4}

D

4he12+e22\frac{4h}{e_{1}^{2} + e_{2}^{2}}

Answer

(e1+e2)2h4\frac{h}{4}

Explanation

Solution

The centre of mass of the system after collision will move up with velocity at (e1+e2)2gh2\frac{\left( e_{1} + e_{2} \right)\sqrt{2gh}}{2}

⇒ 0 = [(e1+e2)22gh]22gh\left\lbrack \frac{\left( e_{1} + e_{2} \right)}{2}\sqrt{2gh} \right\rbrack^{2} - 2gh^{'}h′

= (e1+e2)2h4\frac{\left( e_{1} + e_{2} \right)^{2}h}{4}, Hence, (2) is the correct choice