Question
Question: A drunkard takes a step of 1 m in 1 s. He takes 5 steps forward and 3 steps backward and so on. The ...
A drunkard takes a step of 1 m in 1 s. He takes 5 steps forward and 3 steps backward and so on. The time taken by him to fall in a pit 13 m away from the start is
A
26s
B
31s
C
32s
D
41s
Answer
32s
Explanation
Solution
When he takes 8 steps, the displacement is (5 - 3) = 2m.
Time taken for 8 steps = 8 s
∴ Average velocity = 2/8 = 1/4 ms-1
In the last 5 steps the drunkard will not be able to come backward because he would fall in the pit.
∴ Total displacement required
= 13 – 5 = 8 m
Time required = 8/¼ = 32 s