Question

A drilling machine of power P watts in used to drill a hole in copper block of mass M kg. If the specific heat of copper is s J kg^–10C^–1 and 40% of the power is lost due to heating of the machine, the rise in the temperature of the block in T seconds will be (in ⁰C):

• A. $\frac{0.6PT}{Ms}$
• B. $\frac{0.6P}{MsT}$
• C. $\frac{0.4PT}{Ms}$
• D. $\frac{0.4P}{MsT}$

Answer 1

Answer: (A)

$\frac{0.6PT}{Ms}$

Answer 2

0.6 × P × T = MSDq