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Question

Physics Question on Current electricity

A drift velocity of free electrons in a conductor is υd{{\upsilon }_{d}} , when the current i is flowing in it. If both the radius and current are doubled, the drift velocity will be

A

vd8\frac{{{v}_{d}}}{8}

B

vd4\frac{{{v}_{d}}}{4}

C

vd2\frac{{{v}_{d}}}{2}

D

vd{{v}_{d}}

Answer

vd2\frac{{{v}_{d}}}{2}

Explanation

Solution

i=neAvdi=neA{{v}_{d}} vd=ineA{{v}_{d}}=\frac{i}{neA} where, vd{{v}_{d}} is the drift velociy-of the electron vd1vd2=i1i2×r22r12\frac{{{v}_{{{d}_{1}}}}}{{{v}_{{{d}_{2}}}}}=\frac{{{i}_{1}}}{{{i}_{2}}}\times \frac{r_{2}^{2}}{r_{1}^{2}} =i2i×2n2n2=2=\frac{i}{2i}\times \frac{2{{n}^{2}}}{{{n}^{2}}}=2 vd2=vd12=vd2{{v}_{{{d}_{2}}}}=\frac{{{v}_{{{d}_{1}}}}}{2}=\frac{{{v}_{d}}}{2}