Question

A double charged lithium atom is equivalent to hydrogen whose atomic number is 3. The wavelength of required radiation for emitting electron from first to third Bohr orbit in Li⁺⁺ will be (Ionisation energy of hydrogen atom is 13.6 eV)-

• A. 182.51 Å
• B. 177.17 Å
• C. 142.25 Å
• D. 113.74 Å

Answer 1

Answer: (D)

113.74 Å

Answer 2

$\frac{1}{\lambda}$ = Rz²$\left( \frac{1}{n_{1}^{2}}–\frac{1}{n_{2}^{2}} \right)$