Question

A dominant gene B is responsible for the wild type body color of Drosophila, its recessive allele b produces black body color. A test cross of a wild type female gave 52 black and 58 wild type in the F 1 ​ . If the wild type F 1 ​ females are crossed with black F 1 ​ males, what would be the expected genotypic ratio in the F 2?
A.Homozygous wild : Heterozygous black = 1:1
B.Homozygous wild : Heterozygous wild : Homozygous black = 1:2:1
C.Heterozygous wild : Homozygous black = 1:1
D.All heterozygous black

Answer 1

The Advantage refers to the relationship between the two versions of the gene. An individual obtains two versions of each gene from each parent, called alleles. If the alleles of the gene are different, one allele will be expressed. It is the dominant gene. The role of the other recessive allele was masked.

Complete answer:
Heterozygous: If the two versions are different, the gene has a heterozygous genotype. ...For example, if your hair dye is heterozygous, it may mean that you have one allele for red hair and one allele for brown hair. The relationship between two alleles affects which traits are expressed. The cross begins with the parents’ generation.

One parent is homozygous for one allele, and the other parent is homozygous for the other allele. The descendants form the first generation of filial sons (F1). Each member of the F1 generation is heterozygous, and the phenotype of the F1 generation expresses dominant characteristics. Along these lines, to repeat Mendel's considering current terms, we can't induce a living being's genotype by just watching it’s aggregate.

In reality, Mendel demonstrated that phenotypic characteristics can be covered up in one age, yet reappear in resulting ages. This happens on the grounds that a few alleles are predominant over others, which implies that their aggregate will veil the aggregate related with the latent alleles.Because of strength, there is certifiably not a balanced correspondence between the alleles that a creature has (i.e., its genotype) and the life form's watched aggregate.

The qualities that code for eye and body tone in the organic product fly Drosophila melanogaster. In these flies, the earthy colored eye allele (b) is latent to the ordinary red-eye allele (B). Likewise, the dark body shading allele (e) is passive to the ordinary (yellow-earthy colored) body shading allele (E).

Hence the correct answer is OPTION(C)

Note: If the ratio is approximately 1:1, all wild-type females produced by test crosses of wild-type females are heterozygous. Therefore, when the F1 generation heterozygous wild-type female and the homozygous black male cross, the heterozygous wild-type and the homozygous black-type will be produced in a ratio of 1:1.