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Question: A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating...

A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating force on the rocket is

A

20 dynes

B

20 N

C

22 dynes

D

1000 N

Answer

20 N

Explanation

Solution

F=u(dmdt)=400×0.05=206muNF = u\left( \frac{dm}{dt} \right) = 400 \times 0.05 = 20\mspace{6mu} N