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Question: A disk having plane parallel to the horizontal in moving such that velocity of point P w.r.t ground ...

A disk having plane parallel to the horizontal in moving such that velocity of point P w.r.t ground is 2j^2\widehat{j} m/s as shown in figure. If radius of disk is R = 1 m and the angular speed of disk about vertical axis passing through disk is w = 2rad/sec, the velocity of centre of disc in m/s is –

A

2j^2\widehat{j}

B

2i^+2j^2\widehat{i} + 2\widehat{j}

C

2i^+2j^2\widehat{i} + 2\widehat{j}

D

None

Answer

2i^+2j^2\widehat{i} + 2\widehat{j}

Explanation

Solution

VCG=VCP+VPG{\overset{\rightarrow}{V}}_{CG} = {\overset{\rightarrow}{V}}_{CP} + {\overset{\rightarrow}{V}}_{PG} = 2i^+2j^–2\widehat{i} + 2\widehat{j} m/s