Question

A discrete random variable X has the following probability distribution:

X	1	2	3	4	5	6
P(X)	$\frac{2}{k}$	$\frac{4}{k}$	$\frac{1}{k}$	$\frac{2}{k}$	$\frac{3}{k}$	$\frac{5}{k}$

The value of k is:

• A. $\frac{2}{17}$
• B. 17
• C. 5
• D. $\frac{1}{17}$

Answer 1

Answer: (B)

17

Answer 2

The correct option is (B): 17