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Question: A disc rotating about its axis with angular speed \(\omega_{0}\) is placed lightly (without any tran...

A disc rotating about its axis with angular speed ω0\omega_{0} is placed lightly (without any translational push) on a perfectly frictionless table. The radius of the disc is R. Let vA, vB and vc be the magnitudes of linear velocities of the points A, B and C on the disc as shown. Then

A

vA>vB> vc

B

vA < vB < vc

C

vA = vB< vc

D

vA = vB> vc

Answer

vA = vB> vc

Explanation

Solution

Velocity at point on the disc, v=rωv = r\omega

vA=Rω0\therefore v_{A} = R\omega_{0}

vB=Rω0v_{B} = R\omega_{0}

vC=R2ω0v_{C} = \frac{R}{2}\omega_{0}

vA=vB>vC\therefore v_{A} = v_{B} > v_{C}