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Question

Physics Question on System of Particles & Rotational Motion

A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let vPv_P, vqv_q and vcv_c be the magnitude of velocities of points P,Q and C respectively, then

A

vQ>vC>vPv_Q > v_C > v_P

B

vQ<vC<vPv_Q < v_C < v_P

C

vQ=vP,vC=12vPv_Q=v_P,v_C=\frac{1}{2}v_P

D

vQ<vC>vPv_Q < v_C > v_P

Answer

vQ>vC>vPv_Q > v_C > v_P

Explanation

Solution

In case of pure rolling bottom most point is the instantaneous centre of zero velocity.
Velocity of any point on the disc, v=r?,v=r?, where r is the distance of point from O.
rQ>rC>rPr_Q > r_C > r_P
vQ>vC>vP\therefore v_Q > v_C > v_P
Therefore, the correct option is (a).