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Question

Physics Question on Refraction of Light

A disc is placed on a surface of pond which has refractive index 5/3. A source of light is placed 4 m below the surface of liquid. The minimum radius of disc needed so that light is not coming out is

A

\infty

B

3m

C

6m

D

4m

Answer

3m

Explanation

Solution

θ\theta is the critical angle.
θ=sin1(1/μ)=sin1(3/5)\therefore \, \, \, \, \theta = sin ^{-1} (1/ \mu ) = sin ^{-1} (3/5)
or sinθ=3/5\, \, \, sin \theta = 3/5
tanθ=3/4=r/4orr=3m\therefore \, \, \, tan \theta = 3/4 = r/4 \, \, or \, \, r=3 m