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Question

Physics Question on rotational motion

A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc -

A

velocity is v, acceleration is zero

B

velocity is zero, acceleration is zero

C

velocity is v, acceleration is v2/Rv^2/R

D

velocity is zero, acceleration is v2/Rv^2/R

Answer

velocity is zero, acceleration is v2/Rv^2/R

Explanation

Solution

vA=0v _{ A }=0 (due to pure rolling)
Angular acceleration (for A), a
=Rw2=Rv2R2=R w^{2}=R \frac{v^{2}}{R^{2}}
a=v2R\Rightarrow a=\frac{v^{2}}{R}