Question
Question: A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as s...
A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc.
A
Velocity is v, acceleration is zero
B
Velocity is zero, acceleration is zero
C
Velocity is v, acceleration is Rv2
D
Velocity is zero, acceleration is nonzero
Answer
Velocity is zero, acceleration is nonzero
Explanation
Solution
From figure
Vnet (for lowest point) = v – Rw = v – v = 0
and Acceleration = Rv2+ O = Rv2
(Since linear speed is constant)
Hence (4)