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Question

Question: A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as s...

A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc.

A

Velocity is v, acceleration is zero

B

Velocity is zero, acceleration is zero

C

Velocity is v, acceleration is v2R\frac{v^{2}}{R}

D

Velocity is zero, acceleration is nonzero

Answer

Velocity is zero, acceleration is nonzero

Explanation

Solution

From figure

Vnet (for lowest point) = v – Rw = v – v = 0

and Acceleration = v2R\frac{v^{2}}{R}+ O = v2R\frac{v^{2}}{R}

(Since linear speed is constant)

Hence (4)