Question

A dihybrid plant with incomplete linkage on test cross may produce how many types of plants?
A. 2
B. 4
C. 8
D. 1

Answer 1

Hint:- A hybridization describes a mating experiment between two organisms that are identically hybrid for 2 traits. ... The offspring of the RRYY x rryy cross, which is named the F1 generation, were all heterozygous plants with round, yellow seeds and therefore the genotype RrYy.
Linkage between genes that exhibit some crossing over; intermediate in its effects between independent assortment and complete linkage.

Complete step-by-step solution:- Total possible sort of gametes produced by an organism is 2n
where "n" is the number of genes that the person is heterozygous. A dihybrid is heterozygous for 2 chromosomes and thus forms four differing types of gametes 22= 4 two parental types and two recombinant types. Here, the percent of parental types are going to be higher thanks to the linkage. On test cross, these four gametes may produce to four different phenotypes. to make 8 different gametes, individual should be trihybrid; 23= 8. A monohybrid produces two sorts of gametes 2*1= 2 and homozygotes (AA) form a single sort of gametes.

So, from the above discussion it can be concluded that the correct answer is option B.

Note:- A cross between two pure lines (varieties, strains) that differ in two traits, i.e., allele pairs of particular interest is referred to as a dihybrid cross. In the sense of Mendel, between the alleles of both these loci, there is a relationship of complete dominance - recessive.
For an instance-, RRYY/rryy parents result in F1​ generations that are heterozygous for both R and Y (RrYy).
It will yield 4 dihybrid plants in F2​ offsprings.. The ratio will be 9:3:3:1.