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Question

Question: A differential equation of first order and first degree is...

A differential equation of first order and first degree is

A

x(dydx)2x+a=0x \left( \frac { d y } { d x } \right) ^ { 2 } - x + a = 0

B

d2ydx2+xy=0\frac { d ^ { 2 } y } { d x ^ { 2 } } + x y = 0

C

dy+dx=0d y + d x = 0

D

None of these

Answer

dy+dx=0d y + d x = 0

Explanation

Solution

Option (1) First order and second degree.

Option (2) Second order and first degree.

Option (3) First order and first degree.

i.e., dy+dx=0d y + d x = 0or dydx+1=0\frac { d y } { d x } + 1 = 0.