Solveeit Logo

Question

Question: A dielectric slab of area A and thickness d is inserted between the plates of capacitor of area 2 A ...

A dielectric slab of area A and thickness d is inserted between the plates of capacitor of area 2 A and distance between the plates d with a constant speed v as shown in figure. The capacitor is connected to a battery of emf E. The current in the circuit varies with time as :

A
B
C
D
Answer

4

Explanation

Solution

The capacitance of a parallel plate capacitor with partially inserted dielectric varies linearly with the inserted length. Since the dielectric is inserted at a constant speed, the capacitance varies linearly with time. The current in the circuit connected to a constant voltage source is given by I=EdCdtI = E \frac{dC}{dt}. As C(t)C(t) is a linear function of time during insertion, dCdt\frac{dC}{dt} is a constant. Thus, the current is constant and positive during insertion. Once the dielectric is fully inserted, the capacitance becomes constant, making dCdt=0\frac{dC}{dt}=0, and hence the current drops to zero.