Question

A die is tossed thrice. Find the probability of getting an odd number at least once.

Answer 1

The correct answer is: $\frac{7}{8}$
Probability of getting an odd number in a single throw of a die=$\frac{3}{6}=\frac{1}{2}$
Similarly,probability of getting an even number $=\frac{3}{6}=\frac{1}{2}$
Probability of getting an even number three times$=\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{8}$
Therefore, probability of getting an odd number at least once
=1-Probability of getting an odd number in none of the throws
=1-Probability of getting an even number thrice
$=1-\frac{1}{8}$
$=\frac{7}{8}$