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Question: A die is tossed thrice. A success is getting 1 or 6 on a toss. The mean and the variance of number o...

A die is tossed thrice. A success is getting 1 or 6 on a toss. The mean and the variance of number of successes

A

μ=1,σ2=2/3\mu = 1 , \sigma ^ { 2 } = 2 / 3

B

μ=2/3,σ2=1\mu = 2 / 3 , \sigma ^ { 2 } = 1

C

μ=2,σ2=2/3\mu = 2 , \sigma ^ { 2 } = 2 / 3

D

None of these

Answer

μ=1,σ2=2/3\mu = 1 , \sigma ^ { 2 } = 2 / 3

Explanation

Solution

For binomial distribution, mean=np= n p and variance

=npq= n p q

n=3n = 3 p=26=13p = \frac { 2 } { 6 } = \frac { 1 } { 3 } q=1p=113=23q = 1 - p = 1 - \frac { 1 } { 3 } = \frac { 2 } { 3 }

So, mean (μ)=3×13=1( \mu ) = 3 \times \frac { 1 } { 3 } = 1

Variance (σ2)=3×13×23=23\left( \sigma ^ { 2 } \right) = 3 \times \frac { 1 } { 3 } \times \frac { 2 } { 3 } = \frac { 2 } { 3 }.