Question

A dice is thrown 100 times and the outcomes are recorded as below:-

Outcomes	1	2	3	4	5	6
Frequency	25	20	12	18	15	10

If the dice is thrown once again. What is the probability of getting –
A) Even number
B) Prime number

Answer 1

Here in this question total outcomes are given so we will find favourable outcomes with the help of given data in question and then apply formula of probability that is mentioned below:-
$Probability = \dfrac{{\text{Favourable outcomes}}}{{\text{Total number of outcomes}}}$

Complete step-by-step answer:
As given total times dice being thrown is 100 so we can say that total numbers of outcomes are 100. Now we will find favourable outcomes.
Even number
In table even numbers are 2, 4 and 6 and the frequency of their coming is 20, 18 and 10. So, the total frequency of getting an even number will be a sum of three. This total frequency can also be called as favourable outcomes.
$\Rightarrow 20 + 18 + 10 = 48$
Therefore probability of getting even number= Total frequency of getting even number/ total number of times dice is thrown
$\Rightarrow \dfrac{{48}}{{100}} = 0.48$
Prime number
In table even numbers are 2, 3 and 5 and frequency of their coming is 20, 12 and 15. So, the total frequency of getting an even number will be a sum of three. This total frequency can also be called as favourable outcomes.
$\Rightarrow 20 + 12 + 15 = 47$
Therefore probability of getting prime number= Total frequency of getting prime number/ total number of times dice is thrown
$\Rightarrow \dfrac{{47}}{{100}} = 0.47$

Note: Students may likely make mistakes while taking prime numbers as they consider number 1 as prime number but 1 is not considered as prime number so it should not be taken in the sum otherwise the answer will get incorrect.