Question

A diatomic ideal gas undergoes a thermodynamic change according to the P-V diagram shown in the figure. The total heat given to the gas is nearly (use ln2 = 0.7) –

• A. 2.5 P₀V₀
• B. 1.4 P₀V₀
• C. 39 P₀V₀
• D. 1.1 P₀V₀

Answer 1

Answer: (C)

39 P₀V₀

Answer 2

Q_AB = DU_AB + W_AB W_AB = 0 DU_AB = nRDT

 $\frac { \mathrm { f } } { 2 }$ (DPV)

DU_AB = $\frac { 5 } { 2 }$ (DPV)  Q_AB = 2.5 P₀V₀

Process BC

Q_BC = DU_BC + W_BC  Q_BC = 0 + 2P₀ V₀ ln2 = 1.4 P₀V₀

Q_net = Q_AB + Q_BC = 3.9 P₀V₀