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Question

Question: A diatomic gas molecule has translational, rotational and vibrational degrees of freedom. The \(C_{P...

A diatomic gas molecule has translational, rotational and vibrational degrees of freedom. The CP/CVC_{P}/C_{V} is

A

1.67

B

1.4

C

1.29

D

1.33

Answer

1.33

Explanation

Solution

Degree of freedom f=3f = 3

(Translatory)+2(rotatory) +1(vibratory) = 6

Ž CPCV=γ=1+2f=1+26=43=1.33\frac{C_{P}}{C_{V}} = \gamma = 1 + \frac{2}{f} = 1 + \frac{2}{6} = \frac{4}{3} = 1.33