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Question: A determinant is chosen at random. The set of all determinants of order 2 with elements 0 or 1 only....

A determinant is chosen at random. The set of all determinants of order 2 with elements 0 or 1 only. The probability that value of the determinant chosen is positive, is

A

3/16

B

3/8

C

1/4

D

None of these

Answer

3/16

Explanation

Solution

n=n = Total number of ways =24=16= 2 ^ { 4 } = 16

m=m = Favourable number of ways

Since the value of determinant is positive when it is

1001,1011,1101\left| \begin{array} { l l } 1 & 0 \\ 0 & 1 \end{array} \right| , \left| \begin{array} { l l } 1 & 0 \\ 1 & 1 \end{array} \right| , \left| \begin{array} { l l } 1 & 1 \\ 0 & 1 \end{array} \right| . Hence required probability =316= \frac { 3 } { 16 }