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Question: A dealer sold a VCR and a TV for RS. \[{\mathbf{38560}}\] making profit of \[{\mathbf{12}}\% \] on V...

A dealer sold a VCR and a TV for RS. 38560{\mathbf{38560}} making profit of 12%{\mathbf{12}}\% on VCR and 15%{\mathbf{15}}\% on TV. By selling them for Rs. 38620{\mathbf{38620}}, he would have realized a profit of 15%{\mathbf{15}}\% on VCR and 12%{\mathbf{12}}\% on TV. Find the cost price of each.
A. CP of VCR = Rs. 15000 and CP of TV = Rs. 17000
B . CP of VCR = Rs. 21000 and CP of TV = Rs. 32000
C . CP of VCR = Rs. 18000 and CP of TV = Rs. 16000
D . CP of VCR = Rs. 12000 and CP of TV = Rs. 15000

Explanation

Solution

As we know that cost price (C.P) means the amount which is paid by the seller to acquire the product and selling price (S.P) is the money that is finally received by the seller after selling that same product to any customer.
If the S.P is more than the C.P then there will be profit and if C.P. is more than the S.P. then there will be loss for the seller.
Hence, Profit% is the percent of profit gained by the seller and loss % is percent of loss suffered by the seller.
Profit and Loss for any product is given by:
[\Profit = S.P - C.P]
Loss=C.PS.PLoss = C.P - S.P
Now profit and loss percentage can be calculated by:
[\Profit% = \dfrac{{\Profit}}{{C.P}} \times 100]
Loss%=LossC.P×100Loss\% = \dfrac{{Loss}}{{C.P}} \times 100

Complete step by step solution:
Let C.P of VCR be Rs. X, and C.P of TV be Rs. Y.
S.P of VCR=C.P×100+p100\, = C.P \times \dfrac{{100 + p}}{{100}}
\because P denotes the profit, and to find out the selling price we use the formula:
S.P=C.P×(100+P100)S.P = C.P \times \left( {\dfrac{{100 + P}}{{100}}} \right)
So, the S.P of VCR is = x \times \left( {\dfrac{{100 + 12}}{{100}}} \right)$$$$ = \dfrac{{12}}{{100}}x
Selling price of TV == C.P of TV ×(100+p100) \times \,\left( {\dfrac{{100 + p}}{{100}}} \right)
=y×(100+15100)= \,y \times \left( {\dfrac{{100 + 15}}{{100}}} \right)
=115100y= \dfrac{{115}}{{100}}y
Given total S.P of VCR and TV is:
112100x+115100y=38560\dfrac{{112}}{{100}}x + \dfrac{{115}}{{100}}y = 38560 ________ (1).
By selling them for Rs. 3862038620then:
115100x+112100y=38620\dfrac{{115}}{{100}}x + \dfrac{{112}}{{100}}y = 38620 _________ (2).
Now, we can write equation (1) like this:
112x+115y=3856000112x + 115y = 3856000 _________ (3).
And equation (2)
115x+112y=3862000115x + 112y = 3862000 __________ (4).
In equation (3) we multiply by 115115and in equation (4) we multiply by 112112, we get: -
12880x+13225y=443,440,00012880x + 13225y = 443,440,000 ______ (5).
12880x+12544y=432,544,00012880x + 12544y = 432,544,000 ______ (6).
Subtraction equation (6) from equation (5):
681y=10896000681y = 10896000
y=16000y = 16000
Putting the value of y in equation (5) we get:
12880x+13225×1600=443,440,00012880x + 13225 \times 1600 = 443,440,000
12880x+211,600,000=443,440,00012880x + 211,600,000 = 443,440,000
12880x=231,840,00012880x = 231,840,000
x=18000x = 18000
\therefore C.P of VCR ==Rs. 1800018000.
C.P of TV == Rs. 1600016000

Note: Cost price calculated by using the formula given below
C.P=100100+P%×S.PC.P = \dfrac{{100}}{{100 + P\% }} \times S.P
C.P means cost price and S.P means selling price, and there would be profit only if S.P >> C.P.