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Question

Mathematics Question on Applications of Derivatives

A cylindrical tank of radius 10m is being filled with wheat at the rate of 314cubic mere per hour.Then the depth of the wheat is increasing at the rate of

A

1m/h

B

0.1m/h

C

1.1m/h

D

0.5m/h

Answer

1m/h

Explanation

Solution

The correct answer is A:1m/h1m/h
Let rr be the radius of the cylinder. Then, volume (V)(V) of the cylinder is given by,
V=π(radius)2×heightV=π(radius)^2\times height
=π(10)2h=π(10)^2h
=100πh=100πh
Differentiating with respect to time tt, we have:
dVdt=100πdhdt\frac{dV}{dt}=100π\frac{dh}{dt}
The tank is being filled with wheat at the rate of 314cubic metres per hour.
dVdt=314m3/h∴\frac{dV}{dt}=314m^3/h
Thus, we have:
314=100πdhdt314=100π\frac{dh}{dt}
dhdt=314100(3.14)=314314=1⇒\frac{dh}{dt}=\frac{314}{100(3.14)}=\frac{314}{314}=1
Hence, the depth of wheat is increasing at the rate of 1m/h.1m/h.
The correct answer is A.