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Question: A cylinder of fixed capacity 44.8 litres contains helium gas at standard temperature and pressure. W...

A cylinder of fixed capacity 44.8 litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by 15°C ? (R = 8.31 K mol–1 K–1)

A

265 J

B

310.10 J

C

373.95 J

D

387.97 J

Answer

373.95 J

Explanation

Solution

Since one mole of any ideal gas at NTP occupies a volume of 22.422.4litre.

Therefore, cylinder of fixed capacity 44.844.8litre must contain 3 moles of helium at NTP.

For helium, CV=32RC_{V} = \frac{3}{2}R (monoatomic)

\thereforeHeat needed to raise the temperature,

Q = number of moles × molar specific heat × raise in temperature.

=2×32×15=45R=45×8.31J=373.95J= 2 \times \frac{3}{2} \times 15 = 45R = 45 \times 8.31J = 373.95J