Question

A cylinder of 5 litre capacity, filled with air at N.T.P. is connected with another evacuated cylinder of 30 litres of capacity. The resultant air pressure in both the cylinders will be

• A. 38.85 cm of $Hg$
• B. 21.85 cm of $Hg$
• C. 10.85 cm of $Hg$
• D. 14.85 cm of $Hg$

Answer 1

Answer: (C)

10.85 cm of $Hg$

Answer 2

Here temperature remain constant

So $P_{1}V_{1} = P_{2}V_{2} \Rightarrow 76 \times 5 = P_{2} \times 35$

$\Rightarrow P_{2} = \frac{76 \times 5}{35} = 10.85cm\text{of}hg$