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Question

Physics Question on Nuclear Energy

A cyclotron is used to accelerate protons (11H{}^1_1\text{H}​), Deuterons (12H{}^2_1\text{H}​) and α-particles (24He{}^4_2\text{He}). While exiting under similar conditions, the minimum K.E. is gained by

A

α-particle

B

Proton

C

Deuteron

D

Same for all

Answer

Deuteron

Explanation

Solution

The correct option is (C): K.E.=q2mK.E. =\frac{q^2}{m}
So a deuteron gains the least kinetic energy.