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Question

Physics Question on Uniform Circular Motion

A cyclist starts from the centre OO of a circular park of radius one kilometre, reaches the edge PP of the park, then cycles along the circumference and returns to the centre along QOQO as shown in figure. If the round trip takes ten minutes, the net displacement and average speed of the cyclist (in metre and kilometre per hour) is.........

A

0,10,1

B

π+42,0\frac {\pi+4}{2},0

C

21.4,π+4221.4,\frac {\pi+4} {2}

D

0,21.40,21.4

Answer

0,21.40,21.4

Explanation

Solution

Since, the initial position of cyclist coincides with final position, so his net displacement is zero.
Average speed = total distance travelled  total time taken =\frac{\text { total distance travelled }}{\text { total time taken }}
=OP+PQ+QO10km/min=\frac{O P+P Q+Q O}{10} km / min
=1+π2×1+110km/min=\frac{1+\frac{\pi}{2} \times 1+1}{10} km / min
=π+420×60km/h=\frac{\pi+4}{20} \times 60 km / h
=21.4km/h=21.4 \,km / h