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Question

Physics Question on Motion in a straight line

A cyclist moving on a circular track of radius 40 m40\, m completes half a revolution in 40 s40 \,s. Its average velocity is

A

zero

B

4π m s−14\pi \,m\,s^{-1}

C

2π m s−12\pi \,m\,s^{-1}

D

8π m s−18\pi \,m\,s^{-1}

Answer

2π m s−12\pi \,m\,s^{-1}

Explanation

Solution

Average velocity =DisplacementTime taken=\frac{\text{Displacement}}{\text{Time taken}} =2Rt=2×4040=2 m s−1=\frac{2R}{t}=\frac{2\times40}{40}=2\,m\,s^{-1}