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Question

Physics Question on laws of motion

A cyclist moves in a circular track or radius 100m100\,m . If the coefficient of friction 0.20.2 . Then the maximum speed with which the cyclist can take a turn without leaving inwards, is

A

14.0 m/s

B

140 m/s

C

1.4 m/s

D

9.8 m/s

Answer

14.0 m/s

Explanation

Solution

Given μ=0.2,g=9.8m/s2\mu =0.2,\, g=9.8\, m / s ^{2} r=100mr =100\, m Maximum velocity with which the cyclist can take a circular path of radius rr is v=μrgv=\sqrt{\mu r g} So, v=0.2×100×9.8v=\sqrt{0.2 \times 100 \times 9.8} =196=14m/s=\sqrt{196}=14\, m / s