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Question: A cycle followed by an engine (made of one mole of an ideal gas in a cylinder with a piston) is show...

A cycle followed by an engine (made of one mole of an ideal gas in a cylinder with a piston) is shown in figure.

The heat exchanged by the engine with the surroundings at constant volume is (Take CV = 32\frac { 3 } { 2 } R)

A

(PB – PA)VA

B

12\frac { 1 } { 2 }(PB – PA)VA

C

32\frac { 3 } { 2 } (PB – PA)VA

D

52\frac { 5 } { 2 }(PB – PA)VA

Answer

32\frac { 3 } { 2 } (PB – PA)VA

Explanation

Solution

:

In the given figure, portion AB of the cycle shows increase in pressure/ temperature of gas at constant volume.

Therefore system gains the from the surroundings, then

QAB=UAB=nCvΔTQ _ { A B } = U _ { A B } = n C _ { v } \Delta T QAB=1×CV×ΔT=32R(TBTA)=32(PBVBPAVA)Q _ { A B } = 1 \times C _ { V } \times \Delta T = \frac { 3 } { 2 } R \left( T _ { B } - T _ { A } \right) = \frac { 3 } { 2 } \left( P _ { B } V _ { B } - P _ { A } V _ { A } \right) QAB=32(PBPA)VA(VA=VB)\therefore Q _ { A B } = \frac { 3 } { 2 } \left( P _ { B } - P _ { A } \right) V _ { A } \left( \because V _ { A } = V _ { B } \right)