Question
Question: A current of 9.65 Ampere flowing for 10 minutes deposits 3 g of metal which is monovalent, the atomi...
A current of 9.65 Ampere flowing for 10 minutes deposits 3 g of metal which is monovalent, the atomic mass of metal is a:
A.10
B.50
C.30
D.96.5
Solution
In order to calculate the atomic mass of a metal which is the mean weight possessed by an atom due to protons and neutrons in its nucleus, we will use formula of charge i.e. q=I×t, here I is current, Q is charge and t is time and equivalent weight i.e. Eq. wt. of metal=qWeightofmetal×F, F= faraday's constant.
Complete step by step answer:
According to the question the weight of metal deposited = 3g
Amount of electricity passed through the metal will be; q=I×t.........(1)
Here q represents charge, I represents current and t represents time.
Current (I)=9.65A
Time =10min
Conversion of minutes to second will take multiplication with 60.
⇒10×60=600sec
Substituting the value of current and time in equation 1;
q=I×t
q=9.65×600
q=5790C, C is the unit of charge i.e. coulomb
Therefore the charge is 5790C.
To find the atomic mass of the metal, the formula used is;
Eq. wt. of metal=qWeightofmetal×F, here F represents Faraday’s constant.
Faraday’s constant = 96500
So the, Equivalent weight of atom will be = 57903 ×96500
Equivalent weight of atom = 50gms
In monovalent metals, the equivalent weight of metal will be equal to its atomic weight.
Thus, the Atomic mass of metal = 50g
So, the correct answer is “Option B”.
Note:
Atomic weight and equivalent weight are two different concepts; atomic weight is the sum total of the mass of atom whereas the equivalent weight is weight of an atom divided by its valency represented as valencyweight of atom.
1 coulomb: It is the SI unit of electricity, which is defined as equal to the quantity of electric charge transferred in one second across a conductor of one unit length in which a constant current of one ampere flows.