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Question: A current of 9.65 Ampere flowing for 10 minutes deposits 3 g of metal which is monovalent, the atomi...

A current of 9.65 Ampere flowing for 10 minutes deposits 3 g of metal which is monovalent, the atomic mass of metal is a:
A.10
B.50
C.30
D.96.5

Explanation

Solution

In order to calculate the atomic mass of a metal which is the mean weight possessed by an atom due to protons and neutrons in its nucleus, we will use formula of charge i.e. q=I×tq = I \times t, here I is current, Q is charge and t is time and equivalent weight i.e. Eq. wt. of metal  =Weight  of  metalq×FEq.{\text{ }}wt.{\text{ }}of{\text{ }}metal\; = \dfrac{{Weight\;of\;metal}}{q} \times F, F= faraday's constant.

Complete step by step answer:
According to the question the weight of metal deposited = 3g3g
Amount of electricity passed through the metal will be; q=I×t.........(1)q = I \times t.........(1)
Here q represents charge, I represents current and t represents time.
Current (I)=9.65A(I) = 9.65A
Time =10min = 10min
Conversion of minutes to second will take multiplication with 60.
10×60=600sec\Rightarrow 10 \times 60 = 600sec
Substituting the value of current and time in equation 1;
q=I×tq = I \times t
q=9.65×600q = 9.65 \times 600
q=5790Cq = 5790C, C is the unit of charge i.e. coulomb
Therefore the charge is 5790C5790C.
To find the atomic mass of the metal, the formula used is;
Eq. wt. of metal  =Weight  of  metalq×FEq.{\text{ }}wt.{\text{ }}of{\text{ }}metal\; = \dfrac{{Weight\;of\;metal}}{q} \times F, here F represents Faraday’s constant.
Faraday’s constant = 9650096500
So the, Equivalent weight of atom will be = 57903 ×9650057903{\text{ }} \times 96500
Equivalent weight of atom = 50gms50gms

In monovalent metals, the equivalent weight of metal will be equal to its atomic weight.
Thus, the Atomic mass of metal = 50g

So, the correct answer is “Option B”.

Note:
Atomic weight and equivalent weight are two different concepts; atomic weight is the sum total of the mass of atom whereas the equivalent weight is weight of an atom divided by its valency represented as weight of atomvalency\dfrac{{weight{\text{ }} of {\text{ }}atom}}{{valency}}.
1 coulomb: It is the SI unit of electricity, which is defined as equal to the quantity of electric charge transferred in one second across a conductor of one unit length in which a constant current of one ampere flows.